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CGP EDU Academic Team
Published on: September 12, 2026
Capacitance of a capacitor made by a thin metal foil is $2 \mu F$ . If the foil is folded with paper of thickness 0.15 mm , dielectric constant of paper is 2.5 and width of paper is 400 mm , then length of foil will be
Text Solution
Verified by ExpertsThe correct answer is:
D
If length of the foil is l then $C = \frac{k \varepsilon_0 (l \times b)}{d}$
⇒ ⇒ $2 \times 10^{-6} = \frac{2.5 \times 8.85 \times 10^{-12} (l \times 400 \times 10^{-3})}{0.15 \times 10^{-3}}$
⇒ ⇒ l = 33.9 m
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